Index

How Things Work · Heat pumps: the second law's ceiling

The heat pump

A fridge, an air conditioner and a heat pump run the same loop. Why does one move barely two joules of heat per joule of electricity and another move four?

A fridge, an air conditioner and a heat pump all run one loop: a refrigerant boils cold, gets squeezed hot, and dumps its heat. The gap between those two temperatures is the hill. The panels show the second law's ceiling, a real machine under it, and the same machine against a plain heater.

Board: Cold Is a Lie →

On a narrow screen the three panels stack below the dials, and the table scrolls sideways.

try this Drag Where the refrigerant boils from -25 °C up to +5 °C and watch the ceiling double.

-25 °C
+45 °C
50% of the ceiling

The gap between the two temperatures is the hill. The ceiling comes from the second law alone: the cold side's temperature in kelvin, divided by the gap. The lesson's real cycles reach 46% to 57% of it.

The ceiling

3.54

joules moved per joule paid, at most, over a 70 K hill

The real machine

1.77

joules moved per joule, at 50% of the ceiling

A 70 K hill, the size a fridge climbs. Even a perfect machine moves only 3.54 joules per joule.

564 W of electricity pulls 1,000 W of heat out of the cold side.

Against a heater

361 W

to deliver 1,000 W of warmth, run as a heat pump

A plain heater pays 1,000 W for the same warmth. Heating ceiling 4.54, one more than the cooling ceiling, because the hot side receives the heat moved plus the work paid.

The dial, swept

Every evaporator notch at the current condenser temperature and hardware.

Boils atHillCeilingReal machineW to move 1 kWW to warm 1 kW
-30 °C75 K3.241.62617 W382 W
-25 °C70 K3.541.77564 W361 W
-20 °C65 K3.891.95514 W339 W
-15 °C60 K4.302.15465 W317 W
-10 °C55 K4.782.39418 W295 W
-5 °C50 K5.362.68373 W272 W
0 °C45 K6.073.03329 W248 W
+5 °C40 K6.953.48288 W223 W
+10 °C35 K8.094.04247 W198 W
+15 °C30 K9.604.80208 W172 W

The lesson's real cycles, for comparison

Computed in the lesson from real refrigerant data with CoolProp, not by this page. Set the dials to the same temperatures and compare.

MachineBoils atDumps atComputed COPCeilingShare
fridge (R-600a)-25 °C+45 °C1.663.5447%
room AC (R-410A)+5 °C+45 °C3.426.9549%
heat pump, heating (R-410A)-5 °C+40 °C3.946.9657%

The hill decides, not the hardware

The fridge lifts heat 70 K and its ceiling is 3.54. The AC lifts it 40 K and its ceiling is 6.95. Nothing about the machine changed. Move the hardware dial and every number scales together, but no setting of it lets the fridge catch the AC. Halve the hill and the ceiling roughly doubles, whatever the machine is made of.

The third panel is the reason heat pumps are replacing heaters. Run the loop backward to warm a house and the hot side receives the heat it pulled from outside plus the electricity it paid. A plain heater turns 1,000 W into 1,000 W of warmth. A heat pump lifting heat from -5 °C to +40 °C, at half its ceiling, delivers the same warmth for 251 W.

Limits of this model

The hardware is one number. A real cycle's COP comes from refrigerant property tables, a compressor's efficiency, and the throttling loss at the valve. This page replaces all of that with one fraction of the ceiling. The lesson's three CoolProp cycles land between 46% and 57%, so the default is 50%.

Loop temperatures, not room temperatures. The evaporator has to be colder than the food or the outdoor air it pulls heat from, and the condenser hotter than the room it warms, usually by 5 to 15 K each side. So the hill a heat pump climbs is wider than the gap between outside and your thermostat.

Steady running only. Defrost cycles, start-up and the fan's own power are left out. On a frosty morning a real heat pump spends some of its time melting ice off its outdoor coil.

Sources